Tentukan nilai (√8) pangkat ⅓
Jawaban:
[tex]( \sqrt{8})^{\frac{1}{3}} = (8^{ \frac{1}{2}})^{ \frac{1}{3} } = 8^{ \frac{1}{6} } = \sqrt[6]{8} = 2^{ \frac{3}{6} } = 2^{ \frac{1}{2} } = \sqrt{2} [/tex]
[tex] \sqrt[]{8^{ \frac{1}{3} } } = ( \sqrt{2^{3}))^{ \frac{1}{3} } } =2^{ \frac{3}{3} } = \sqrt{2}^{1} = \sqrt{2} [/tex]
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